SftTree/OCX 7.5 - ActiveX Tree Control

GetPosition Method, SftTreeSplitter Object

Returns the coordinates of the splitter bar.

Syntax

VB.NET	object.GetPosition(ByRef Left As Single, ByRef Top As Single, ByRef Width As Single, ByRef Height As Single)
VB	object.GetPosition(Left As Single, Top As Single, Width As Single, Height As Single)
C#.NET	void object.GetPosition(out float Left, out float Top, out float Width, out float Height);
VC++	HRESULT object->GetPosition(float* Left, float* Top, float* Width, float* Height);
C	HRESULT object->raw_GetPosition(float* Left, float* Top, float* Width, float* Height);

object

A SftTreeSplitter object.

Left

Returns the horizontal position relative to the top, left corner of the tree control. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Top

Returns the vertical position relative to the top, left corner of the tree control. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Width

Returns the width of the splitter bar. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Height

Returns the height of the splitter bar. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Comments

The GetPosition method returns the coordinates of the splitter bar.

The GetPosition and Splitter.GetPositionPix methods are synonyms, but may use different coordinate systems.

The Splitter.Width property is used to define the width of the splitter bar. The Splitter.Offset defines the horizontal position of the splitter bar.

See Also SftTreeSplitter Object | Object Hierarchy

Documentation

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