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GetPosition Method, SftTreeFooter Object

Returns the coordinates of the footer.

Syntax

VB.NETBoolean = object.GetPosition(ByRef Left As Single, ByRef Top As Single, ByRef Width As Single, ByRef Height As Single, ByRef Span As Short) As Boolean
VBBoolean = object.GetPosition(Left As Single, Top As Single, Width As Single, Height As Single, Span As Integer) As Boolean
C#.NETbool Boolean = object.GetPosition(out float Left, out float Top, out float Width, out float Height, out short Span);
VC++VARIANT_BOOL Boolean = object->GetPosition(float* Left, float* Top, float* Width, float* Height, short* Span);
CHRESULT object->raw_GetPosition(float* Left, float* Top, float* Width, float* Height, short* Span, VARIANT_BOOL* Boolean);

object

A SftTreeFooter object.

Left

Returns the horizontal position relative to the top, left corner of the tree control. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Top

Returns the vertical position relative to the top, left corner of the tree control. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Width

Returns the width of the column footer. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Height

Returns the height of the column footer. The units used depend on the container (Visual Basic, Visual C++, etc.) and the coordinate system used.

Span

Returns the number of columns that the column footer occupies. If cell merging is allowed and the column footer merges into an adjacent column footer, a column footer can span more than one column.

Boolean

BooleanDescription
TrueThe column footer is displayed and visible.
FalseThe column footer is not visible. The returned coordinates are not valid.

Comments

The GetPosition method returns the coordinates of the footer.

The GetPosition and Footer.GetPositionPix methods are synonyms, but may use different coordinate systems.

To retrieve the coordinates of all combined column footers, use Footers.GetPosition instead.

See Also SftTreeFooter Object | Object Hierarchy


Last Updated 08/13/2020 - (email)
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