SplitColumn Property, SftTree Object
Defines the number of columns displayed in the left pane of a split tree control.
Deprecated - Provided for compatibility with earlier versions only - Use Splitter.Column instead
Syntax
Get
| VB.NET | Count = object.SplitColumn As Short |
| VB | Count = object.SplitColumn As Integer |
| C#.NET | short Count = object.SplitColumn; |
| VC++ | short Count = object->SplitColumn;
short Count = object->GetSplitColumn(); |
| C | HRESULT object->get_SplitColumn(short* Count); |
Put
| VB.NET | object.SplitColumn = Count As Short |
| VB | object.SplitColumn = Count As Integer |
| C#.NET | short object.SplitColumn = Count; |
| VC++ | short object->SplitColumn = Count;
void object->PutSplitColumn(short Count); |
| C | HRESULT object->put_SplitColumn(short Count); |
object
A SftTree object.
Count
Defines the number of columns displayed in the left pane of a split tree control. The number specified must be between 1 and the total number of columns-1.
Comments
Deprecated - Provided for compatibility with earlier versions only - Use Splitter.Column instead
The SplitColumn property defines the number of columns displayed in the left pane of a split tree control.
The total number of columns is defined using the ColumnsObj.Count property.
Examples
VB6
Charset = 0
Weight = 400
Underline = 0 'False
Italic = 0 'False
Strikethrough = 0 'False
EndProperty
EndProperty
BeginProperty Splitter {9EBAA94A-293D-44FA-9989-08F078763A1F}
SplitColumn = 0
Object.Visible = 0
OffsetPix = 0
WidthPix = 7
EndProperty
BeginProperty Column(0) {9EBAA938-293D-44FA-9989-08F078763A1F}
BackColor = -1
CellHAlign = 0 View Entire Sample Code
See Also SftTree Object | Object Hierarchy
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